Pickaxe Q

[Kortak]

oke..well i made 4 new pickaxes

Q26 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q27 Pickaxe
Q33 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q28 Pickaxe
Q37 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q30 Pickaxe
Q41 iron (x4) + Q36 Branch +q43 Anvil +q35 Hammer : Q38 Pickaxe

I made low pickaxes so im not softcapped or anything by stats

[Kortak]

so data from 6 pickaxes with same anvil and hammer..and yes there q is accurate and each pickaxe i used 4x the same q ore

Q22 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q25 Pickaxe
Q26 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q27 Pickaxe
Q33 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q28 Pickaxe
Q26 iron (x4) + Q20 Branch +q43 Anvil +q35 Hammer : Q30 Pickaxe
Q37 iron (x4) + Q10 Branch +q43 Anvil +q35 Hammer : Q30 Pickaxe
Q41 iron (x4) + Q36 Branch +q43 Anvil +q35 Hammer : Q38 Pickaxe

[Kortak]

I think i figured it out

Formula is

Qore*2 + Qbranch*2 + (QAnvil+Qhammer)*1.5 /7

[Snk]

This formula can't be based on the data you've collected, no formula (with just these components) can in fact. Either there's some capping involved or your data is wrong.

Edit: I was wrong on the part of possibility, IF components are rounded down mid-way then the data might be correct (but in such case formula is incomplete by that rounding).

[Kortak]

dunno..but wiki formula is not correct.. i made a new Pickaxe

Q44 Iron + Q36 Branch + Q45 Anvil + Q43 Hammer. I got a Q41 Pickaxe



Wiki Formula : Qmetal+Qwood+qAnvil+QHammer/4 should give me a Q42 Pickaxe . (44+36+45+43=168) /4 = 42 This formula sucks balls



Anyways...formula i still hold correct is

(2*Qmetal + 2*Qwood + 1.5*Qanvil + 1.5*QHammer) /7

2*44 + 2*36 + 1.5 * (45+43) / 7 = 41,7 TADA Q41 pickaxe. correct formula


see you