63 Tables needs 24 cupboards per batch (14x14 setup can fit room for 2 to 3 batches)
Pre-update Ideas:
I think the space needed to have a large silk farms is major part of its value; So I set up a system of equations to look at the number of leaves(meals) & worms per container…
[Z] = (XY+4Y)/4
W = XY/4
Let:
Z be the size of container
Y be the number of leaves
X be the number of "meals" per leaf.
W be the number of worms
Set Z = 64
Solve for the number of leaves (Y)
64 = Y*(X+4)/4
Y = 256 / X+4
Solve for number of Worms (W)
W = [X(256 / X+4)]/4
W = (64*X)/(X+4)
Current “meal” count on a leaf is 1
W = (64*1)/(4+1)
Y = 256 / X+4
12.8 Worms
51.2 Leaves
With 12 worms in a cupboard, each worm needs 4 meals
So 48 leaves will leave us with 4 unused spaces. (Soft size of 60)
Projected “meal” count on a leaf as 50
W = (64*50)/(4+50)
Y = 256 / (50+4)
W = 59.259
Y = 4.740
With 59 worms and 5 leaves we will fill a cupboard. (*4.917 worm to storage buff)
The needed meals math checks out 59*4 <= 5*50 a remaining fraction of leafs 14/50
Let's look at the whole system.
[Z] = (XY+4Y)/4
W+Y <= Z
X%4=0 (to remove fractional leaves, per feed cycle)
Solving the system of equations we see one solution for X at 12.
Which would be 48 worms, 16 leaves; (with 12 meals per leaf)
If mulberry trees had 20 total leaves, at 12 meals per we would see a slight Nerf to total meals per tree.
Alternatively, we can drop the %mod calculation back out of the system; If mulberry trees had 16 total leaves, we’d get a slight buff at 16 meals per leaf to the tree at 256 meals. (to keep total meals per tree closer the to same) We would still get a 4.25 buff on worms per cupboard (if meals are 16, worms are 51, leaves are 13);
[Z] = (XY+4Y)/4
W = XY/4
Let:
Z be the size of container
Y be the number of leaves
X be the number of "meals" per leaf.
W be the number of worms
Set Z = 64
Solve for the number of leaves (Y)
64 = Y*(X+4)/4
Y = 256 / X+4
Solve for number of Worms (W)
W = [X(256 / X+4)]/4
W = (64*X)/(X+4)
Current “meal” count on a leaf is 1
W = (64*1)/(4+1)
Y = 256 / X+4
12.8 Worms
51.2 Leaves
With 12 worms in a cupboard, each worm needs 4 meals
So 48 leaves will leave us with 4 unused spaces. (Soft size of 60)
Projected “meal” count on a leaf as 50
W = (64*50)/(4+50)
Y = 256 / (50+4)
W = 59.259
Y = 4.740
With 59 worms and 5 leaves we will fill a cupboard. (*4.917 worm to storage buff)
The needed meals math checks out 59*4 <= 5*50 a remaining fraction of leafs 14/50
Let's look at the whole system.
[Z] = (XY+4Y)/4
W+Y <= Z
X%4=0 (to remove fractional leaves, per feed cycle)
Solving the system of equations we see one solution for X at 12.
Which would be 48 worms, 16 leaves; (with 12 meals per leaf)
If mulberry trees had 20 total leaves, at 12 meals per we would see a slight Nerf to total meals per tree.
Alternatively, we can drop the %mod calculation back out of the system; If mulberry trees had 16 total leaves, we’d get a slight buff at 16 meals per leaf to the tree at 256 meals. (to keep total meals per tree closer the to same) We would still get a 4.25 buff on worms per cupboard (if meals are 16, worms are 51, leaves are 13);
