noindyfikator wrote:@Clemins
easy
https://www.boxentriq.com/code-breaking/cryptogram
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To solve the equation given the values of \( n \) and \( k \):
\[ y = \frac{8k^8 - \cos(2k)}{\sin\left(\frac{1}{2}k\right)} \div (9e^n \times 5) \]
where \( n = 0 \) and \( k = 4.835 \), follow these steps:
First, substitute the given values for \( n \) and \( k \):
\[ y = \frac{8(4.835)^8 - \cos(2 \times 4.835)}{\sin\left(\frac{1}{2} \times 4.835\right)} \div (9e^0 \times 5) \]
Since \( e^0 = 1 \), the equation simplifies to:
\[ y = \frac{8(4.835)^8 - \cos(9.67)}{\sin(2.4175)} \div 45 \]
Now, let's calculate the components step by step.
1. Compute \( 8(4.835)^8 \):
\[ 8(4.835)^8 \approx 8 \times 1756012.521 \approx 14048100.168 \]
2. Compute \( \cos(9.67) \):
\[ \cos(9.67) \approx -0.927 \]
3. Compute \( \sin(2.4175) \):
\[ \sin(2.4175) \approx 0.6618 \]
Putting these values into the equation:
\[ y = \frac{14048100.168 - (-0.927)}{0.6618} \div 45 \]
\[ y = \frac{14048100.168 + 0.927}{0.6618} \div 45 \]
\[ y \approx \frac{14048101.095}{0.6618} \div 45 \]
\[ y \approx 21225807.397 \div 45 \]
\[ y \approx 471684.61 \]
Therefore, the value of \( y \) is approximately 471684.61.
Not quite!
As I mentioned in a follow-up to my original post, when I created the function, I failed to account for different calculators and calculating programs rounding differently.
That being said, when you get an answer, I recommend rounding to the nearest whole number, and Desmos will give you the "correctly" rounded answer as long as you enter the function correctly.
https://www.desmos.com/calculatorThe more precise number for "k" (just in case) = --- / ...- .... .-.. .-. -.-. .--- / .-- ..-. .-.. .. / --. ..-. --.. . -.- / ...- --.. -..- -.-- -.- / -.- -.-- .. ...- ...- / .-- ..-. .-.. .. / .--- --.. --- / .-- ..-. .-.. .. / .-- ..-. .-.. .. / .--- ...- -- ...- . / .--- ...- -- ...- . / -.- -. ..-. / .-- --.. -- ...- / -.- -. ..-. / --.- ...- .. ..-. / ..-. . ...- / -.- -. ..-.
Also, the answer that you got there is incorrect, you're almost there, though
