We all knew this day would come.

freckleskitty · Post by **freckleskitty** » Thu Jun 24, 2010 3:16 am

And it has.

Igglebert · Post by **Igglebert** » Thu Jun 24, 2010 3:22 am

Oh happy days! Drinks all around!

DarkhVorTeX · Post by **DarkhVorTeX** » Thu Jun 24, 2010 2:45 pm

What's the point of censoring names on the wiki? Given your post date, one could easily check the activity log and figure out whose names you censored. It's not like editing the wiki makes you a criminal.

Kahim · Post by **Kahim** » Fri Jun 25, 2010 3:08 am

It is a false sense of security, kinda like keys and gates.

jibbeil · Post by **jibbeil** » Fri Jun 25, 2010 5:56 pm

DarkhVorTeX wrote:What's the point of censoring names on the wiki? Given your post date, one could easily check the activity log and figure out whose names you censored. It's not like editing the wiki makes you a criminal.

i know who made the last 3 edits on the bottom of the image

DukeBenjy · Post by **DukeBenjy** » Fri Jun 25, 2010 6:14 pm

The server has been down for around 16 hours, that is 1 6 of many that'll appear in 3's. 2 numbers within the number 16 equate to the number 3 being doubled, and due to the number 3, there must be 3 of what is tripled or doubled, thus, 666.

I'm hiding in my saferoom. I'm safe, for now.

Potjeh · Post by **Potjeh** » Fri Jun 25, 2010 6:25 pm

Now, for extra credit, connect it to these numbers: 4 8 15 16 23 42.

DukeBenjy · Post by **DukeBenjy** » Fri Jun 25, 2010 6:38 pm

Potjeh wrote:4 8 15 16 23 42.

The 4 is half of the 8, which awards yourself the number 2. With the 2 in hand, you can add the 3 numbers; 4, 8, and 2 together to get 14, due to the 1 in '14', it must be added to the 4 in '14' to make 5, and considering the previously mentioned, 2, there must be 2 digits. 0 is not enough, so 1 is implemented to create 15. This may be done once again to justify the number 2 (Carrying out the process twice) to create 16. By adding the 1 in '16' to a 6, which is also found in '16', you've acquired yourself a 7, which can be used to add to the original number of '16' to get 23. A simple solution to the final number is the multiplication of the penultimate number 23 by the original number acquired via means of deduction; '2', and then the subtraction of the original and first number '4' to acquire the last number of 42.

Potjeh · Post by **Potjeh** » Fri Jun 25, 2010 6:46 pm

Yeah, but how does that relate to server being down?

DukeBenjy · Post by **DukeBenjy** » Fri Jun 25, 2010 6:49 pm

Potjeh wrote:Yeah, but how does that relate to server being down?

It's all in the numbers, sir.

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