Pickaxe Q

[daemmonium]

I'm still having problems with the results of the Wiki's formula, and I can't seem to decipher the actual formula.

q Pickaxe = (2*rounded Down((av. q metal + q branch)/2) + q Anvil + q Smithy's Hammer)/4

That's the wiki's formula. My last 2 pickaxes were:

qCast 27 qBranch 12 qAnvil 27 qHammer 27
2*rounded down(27 + 12)/2 = 38 . (38+27+27)/4 = q23 Pickaxe. But I got a q22.

Now with a q15 branch.
2*rounded down(27 + 15)/2 = 42 . (42+27+27)/4 = q24 Pickaxe. But I got a q23.

Unless the Anvils formula isnt average qCast, then I dont get it.
And it doesnt seem to be a snowball effect from roundings. According to my math, my qCast are more like q27.6~

[sabinati]

formula is wrong, obviously. see if you can use your collected data to fix it.

[zen_soup]

I have never experimented with pickaxe q but considering how most smithing recipes work i'd say (2*iron+branch)/3 softcapped by anvil and hammer q seems quite possible. Plus it fits your results

[kralmir]

the first formula is true, it's more likely you misjudge the q of your anvil.

or at least the formula was true in the old world.


just test a completely different hammer above q 23 and see if it does anything other then softcap.

[daemmonium]

I have never experimented with pickaxe q but considering how most smithing recipes work i'd say (2*iron+branch)/3 softcapped by anvil and hammer q seems quite possible. Plus it fits your results

It seems to be this way sir. It fits both of my last tries, and my previous one.

[Kortak]

Formula wiki is wrong.. q Pickaxe = (avg. q metal + q branch + q Anvil + q Smithy's Hammer)/4 ) (wrong)

Formula mentioned in this thread also doesnt fit my data : (2*iron+branch)/3 softcapped by anvil and hammer q (wrong)


trying to figure out right formula

some data of mine
Q22 iron (4xsame Q) Q10 wood Q43 anvil Q35 hammer : 25q pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q35 hammer : 30Q Pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q43 hammer : 31Q Pickaxe
Q32 iron (4xsame Q) Q36 wood Q43 anvil Q43 hammer : 37Q Pickaxe
Q44 iron (4xsame Q) Q36 wood Q43 anvil Q43 hammer : 40Q Pickaxe

[Hecarim]

This thread is 2 years old

[NOOBY93]

This thread is 2 years old

Better than creating a new thread.

[Arcanist]

So... ( 3((3*iron + branch)/4) + ((anvil+hammer)/2) ) / 4

Q22 iron (4xsame Q) Q10 wood Q43 anvil Q35 hammer : 25q pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q35 hammer : 30Q Pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q43 hammer : 31Q Pickaxe
Q32 iron (4xsame Q) Q36 wood Q43 anvil Q43 hammer : 37Q Pickaxe
Q44 iron (4xsame Q) Q36 wood Q43 anvil Q43 hammer : 40Q Pickaxe

( 3 ((3*22 + 10)/4) + ((43+35)/2) ) / 4 =
( 3 (19) + 39 ) /4 = 24

( 3 ((3*26 + 20)/4 + 39 ) /4 =
( 3 (24.5) + 39) / 4 = 28.125

Alright... Lets try 2*iron + branch / 3

( 3 ((2*22 + 10)/3) + ((43+35)/2) ) / 4 =
( 3 (18) + 39 ) /4 = 23.25

( 3 ((2*26 + 20)/3) + 39 ) /4 =
( 3 (24) + 39) / 4 = 27.25

Alright, Let's go the other way... 4*iron + branch /5

( 3 ((4*22 + 10)/5) + ((43+35)/2) ) / 4 =
( 3 (19.6) + 39 ) /4 = 24.45

( 3 ((4*26 + 20)/5) + 39 ) /4 =
( 3 (24.8) + 39) / 4 = 28.35

5*iron + branch / 6

( 3 ((5*22 + 10)/6) + ((43+35)/2) ) / 4 =
( 3 (20) + 39 ) /4 = 24.75

( 3 ((5*26 + 20)/6) + 39 ) /4 =
( 3 (25) + 39) / 4 = 28.5

FFFUUUUUU

9*iron + branch / 10

( 3 ((9*22 + 10)/10) + ((43+35)/2) ) / 4 =
( 3 (20.8) + 39 ) /4 = 25.35

( 3 ((9*26 + 20)/10) + 39 ) /4 =
( 3 (25.4) + 39) / 4 = 28.8

So it's weighted VERY heavily on the metal q
If someone can do some tests with low q metal, high q branch
And high q metal, low q branch, that would be very helpful for figuring out the exact formula

EDIT:

I just saw this:

Quality for all full metal products are calculated with the formula: quality = (qMetal*4 + qAnvil*1.5 +qHammer*1.5)/7

So the anvil and hammer matter more than I thought.

It might be someing like

( 4((3*cast + branch)/4) + 1.5*anvil + 1.5*hammer) / 7

Let's try one more...

Q22 iron (4xsame Q) Q10 wood Q43 anvil Q35 hammer : 25q pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q35 hammer : 30Q Pickaxe

(4((3*22 + 10) / 4) + 1.5 * 43 + 1.5 * 35 ) / 7
(4(19) + 64.5 + 52.5) / 7 = 27.57

(4((3*26 + 20) / 4) + 1.5 * 43 + 1.5 * 35 ) / 7
(4(24.5) + 64.5 + 52.5) / 7 = 30.7

Close but no cigar.

Please more tests with a large difference between wood q and metal q

[Hecarim]

This thread is 2 years old

Better than creating a new thread.

I guess

some data of mine
Q22 iron (4xsame Q) Q10 wood Q43 anvil Q35 hammer : 25q pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q35 hammer : 30Q Pickaxe
Q26 iron (4xsame Q) Q20 wood Q43 anvil Q43 hammer : 31Q Pickaxe
Q32 iron (4xsame Q) Q36 wood Q43 anvil Q43 hammer : 37Q Pickaxe
Q44 iron (4xsame Q) Q36 wood Q43 anvil Q43 hammer : 40Q Pickaxe

I think there is something wrong with the information. Are you sure it is 100% accurate?

I tried doing q iron + q wood + (q anvil + hammer /2) /3, but the numbers are slightly off..


Ugh, I'm not good at this.